What is the answer to 2log_{2}(x)-log_{2}(x+8)=2 ?

The answer to 2log_{2}(x)-log_{2}(x+8)=2 is x=8

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2log_{2}(x)-log_{2}(x+8)=2

2 lo g_{2} (x) - lo g_{2} (x + 8) = 2

x = 8

Solution steps

2 lo g_{2} (x) - lo g_{2} (x + 8) = 2

Apply log rules

x^{2} = 4 (x + 8)

Solve

x^{2} = 4 (x + 8) : x = 8, x = - 4

x = 8, x = - 4

Verify Solutions:

x = 8

True

, x = - 4

False

The solution is

x = 8

14 = lo g_{2} (m)

lo g_{5} (x - 1) = 1

2 lo g_{10} (8 n + 4) + 6 = 10

ln (2 x + 1) + 3 = 5

ln (9 x + e) = - 6

What is the answer to 2log_{2}(x)-log_{2}(x+8)=2 ?
The answer to 2log_{2}(x)-log_{2}(x+8)=2 is x=8
Solve for x: 2log_{2}(x)-log_{2}(x+8)=2
The solution is x=8