What is the answer to log_{2}(x-3)+log_{2}(x-2)=1 ?

The answer to log_{2}(x-3)+log_{2}(x-2)=1 is x=4

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log_{2}(x-3)+log_{2}(x-2)=1

lo g_{2} (x - 3) + lo g_{2} (x - 2) = 1

x = 4

Solution steps

lo g_{2} (x - 3) + lo g_{2} (x - 2) = 1

Apply log rules

(x - 3) (x - 2) = 2

Solve

(x - 3) (x - 2) = 2 : x = 4, x = 1

x = 4, x = 1

Verify Solutions:

x = 4

True

, x = 1

False

The solution is

x = 4

ln (t - 2) = ln (8) - ln (t)

lo g_{10} (4 x) = lo g_{10} (7)

lo g_{3} (x + 6) - lo g_{3} (x - 2) = 2

l (v) = v ln (1 - v^{2})

- 3 x + 9 = lo g_{2} (x)

What is the answer to log_{2}(x-3)+log_{2}(x-2)=1 ?
The answer to log_{2}(x-3)+log_{2}(x-2)=1 is x=4
Solve for x: log_{2}(x-3)+log_{2}(x-2)=1
The solution is x=4