What is 1/(n^3)*((n-1)(2n-1))/6 ?

The solution to 1/(n^3)*((n-1)(2n-1))/6 is ((n-1)(2n-1))/(6n^3)

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simplify 1/(n^3)*((n-1)(2n-1))/6

simplify

\frac{1}{n ^{3}} \cdot \frac{( n - 1 ) ( 2 n - 1 )}{6}

\frac{( n - 1 ) ( 2 n - 1 )}{6 n ^{3}}

Solution steps

\frac{1}{n ^{3}} \cdot \frac{( n - 1 ) ( 2 n - 1 )}{6}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( n - 1 ) ( 2 n - 1 )}{n ^{3} \cdot 6}

Apply rule:

1 \cdot a = a

1 \cdot (n - 1) (2 n - 1) = (n - 1) (2 n - 1)

= \frac{( n - 1 ) ( 2 n - 1 )}{n ^{3} \cdot 6}

= \frac{( n - 1 ) ( 2 n - 1 )}{6 n ^{3}}

\frac{2 ( x + 5 )}{3} = 8

- 24 + x = - 3

x^{2} + 10 x + 1 = 0

(b^{2} + 8 b - 9) - (11 b^{2} - 4 b + 7)

4 x^{2} - 1 y^{4} x^{2} - 4 x + 1

What is 1/(n^3)*((n-1)(2n-1))/6 ?
The solution to 1/(n^3)*((n-1)(2n-1))/6 is ((n-1)(2n-1))/(6n^3)