What is the answer to log_{7}(x-3)+log_{7}(x+3)=1 ?

The answer to log_{7}(x-3)+log_{7}(x+3)=1 is x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{7}(x-3)+log_{7}(x+3)=1

lo g_{7} (x - 3) + lo g_{7} (x + 3) = 1

x = 4

Solution steps

lo g_{7} (x - 3) + lo g_{7} (x + 3) = 1

Apply log rules

(x - 3) (x + 3) = 7

Solve

(x - 3) (x + 3) = 7 : x = 4, x = - 4

x = 4, x = - 4

Verify Solutions:

x = 4

True

, x = - 4

False

The solution is

x = 4

lo g_{2} (lo g_{5} (x)) = 1

lo g_{2} (lo g_{5} (x)) = 2

lo g_{2} (5 - 2 x) = - 3

2 lo g_{3} (x) = 18

ln (x + 1) = 1

What is the answer to log_{7}(x-3)+log_{7}(x+3)=1 ?
The answer to log_{7}(x-3)+log_{7}(x+3)=1 is x=4
Solve for x: log_{7}(x-3)+log_{7}(x+3)=1
The solution is x=4