What is the answer to log_{2}(x+1)+log_{2}(x-3)=5 ?

The answer to log_{2}(x+1)+log_{2}(x-3)=5 is x=7

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log_{2}(x+1)+log_{2}(x-3)=5

lo g_{2} (x + 1) + lo g_{2} (x - 3) = 5

x = 7

Solution steps

lo g_{2} (x + 1) + lo g_{2} (x - 3) = 5

Apply log rules

(x + 1) (x - 3) = 32

Solve

(x + 1) (x - 3) = 32 : x = 7, x = - 5

x = 7, x = - 5

Verify Solutions:

x = 7

True

, x = - 5

False

The solution is

x = 7

2 lo g_{3} (x) - 3 = 4

lo g_{3} (x - 5) + lo g_{3} (x - 3) = 1

lo g_{2} (x^{2} + 2 x) = 3

4.5 = lo g_{10} (x)

ln (x - 2) + ln (x - 3) = ln (2)

What is the answer to log_{2}(x+1)+log_{2}(x-3)=5 ?
The answer to log_{2}(x+1)+log_{2}(x-3)=5 is x=7
Solve for x: log_{2}(x+1)+log_{2}(x-3)=5
The solution is x=7