What is the answer to ln(x-2)+ln(x+1)=2 ?

The answer to ln(x-2)+ln(x+1)=2 is x=(1+sqrt(4e^2+9))/2

Solve for x: ln(x-2)+ln(x+1)=2

The solution is x=(1+sqrt(4e^2+9))/2

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ln (x - 2) + ln (x + 1) = 2

x = \frac{1 + 4 e ^{2} + 9}{2}

Decimal Notation

x = 3.60468 \dots

Solution steps

ln (x - 2) + ln (x + 1) = 2

Apply log rules

(x - 2) (x + 1) = e^{2}

Solve

(x - 2) (x + 1) = e^{2} : x = \frac{1 + 4 e ^{2} + 9}{2}, x = \frac{1 - 4 e ^{2} + 9}{2}

x = \frac{1 + 4 e ^{2} + 9}{2}, x = \frac{1 - 4 e ^{2} + 9}{2}

Verify Solutions:

x = \frac{1 + 4 e ^{2} + 9}{2}

True

, x = \frac{1 - 4 e ^{2} + 9}{2}

False

The solution is

x = \frac{1 + 4 e ^{2} + 9}{2}

3 lo g_{10} (2 x - 4) = x - 3

lo g_{\frac{2}{x}} (8) = 3

- 1.5 = 10 lo g_{10} (\frac{x}{1})

lo g_{9} (4 x + 1) = 2

lo g_{10} (2 x) - lo g_{10} (x - 1) = 1

What is the answer to ln(x-2)+ln(x+1)=2 ?
The answer to ln(x-2)+ln(x+1)=2 is x=(1+sqrt(4e^2+9))/2
Solve for x: ln(x-2)+ln(x+1)=2
The solution is x=(1+sqrt(4e^2+9))/2