What is the answer to ln(2)+ln(4x-1)=ln(2x+5) ?

The answer to ln(2)+ln(4x-1)=ln(2x+5) is x= 7/6

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ln(2)+ln(4x-1)=ln(2x+5)

ln (2) + ln (4 x - 1) = ln (2 x + 5)

x = \frac{7}{6}

Decimal Notation

x = 1.16666 \dots

Solution steps

ln (2) + ln (4 x - 1) = ln (2 x + 5)

Apply log rules

2 (4 x - 1) = 2 x + 5

Solve

2 (4 x - 1) = 2 x + 5 : x = \frac{7}{6}

x = \frac{7}{6}

Verify Solutions:

x = \frac{7}{6}

True

The solution is

x = \frac{7}{6}

ln (x - 2) + ln (x + 3) = 0

lo g_{2} (x + 2) = 2

\frac{1 - 2 ln ( x )}{x ^{3}} = 0

2 lo g_{x} (3) + lo g_{3} (x) - 3 = 0

1.5 = lo g_{10} (x)

What is the answer to ln(2)+ln(4x-1)=ln(2x+5) ?
The answer to ln(2)+ln(4x-1)=ln(2x+5) is x= 7/6
Solve for x: ln(2)+ln(4x-1)=ln(2x+5)
The solution is x= 7/6