What is the answer to 2log_{2}(x)-log_{2}(x+5)=4 ?

The answer to 2log_{2}(x)-log_{2}(x+5)=4 is x=20

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2log_{2}(x)-log_{2}(x+5)=4

2 lo g_{2} (x) - lo g_{2} (x + 5) = 4

x = 20

Solution steps

2 lo g_{2} (x) - lo g_{2} (x + 5) = 4

Apply log rules

x^{2} = 16 (x + 5)

Solve

x^{2} = 16 (x + 5) : x = 20, x = - 4

x = 20, x = - 4

Verify Solutions:

x = 20

True

, x = - 4

False

The solution is

x = 20

lo g_{0.4} (x) = - 3

lo g_{7} (4 x) + 3 lo g_{7} (5) = 5

lo g_{4} (x) = \frac{1}{4}

ln (x^{2} + 7 x + 12) - ln (x + 4) = 0

5 lo g_{2} (x) - lo g_{4} (x) = 3

What is the answer to 2log_{2}(x)-log_{2}(x+5)=4 ?
The answer to 2log_{2}(x)-log_{2}(x+5)=4 is x=20
Solve for x: 2log_{2}(x)-log_{2}(x+5)=4
The solution is x=20