What is the answer to log_{5}(7-x)=log_{5}(1-x)+2 ?

The answer to log_{5}(7-x)=log_{5}(1-x)+2 is x= 3/4

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log_{5}(7-x)=log_{5}(1-x)+2

lo g_{5} (7 - x) = lo g_{5} (1 - x) + 2

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

lo g_{5} (7 - x) = lo g_{5} (1 - x) + 2

Apply log rules

7 - x = (1 - x) \cdot 25

Solve

7 - x = (1 - x) \cdot 25 : x = \frac{3}{4}

x = \frac{3}{4}

Verify Solutions:

x = \frac{3}{4}

True

The solution is

x = \frac{3}{4}

5 = ln (- 5 x + 3)

15.328 = - 1.451 ln (x) + 24.036

3 lo g_{x} (3) + lo g_{3} (x) = 4

lo g_{x - 4} (4) = \frac{3}{2}

lo g_{10} (x) = 0.2

What is the answer to log_{5}(7-x)=log_{5}(1-x)+2 ?
The answer to log_{5}(7-x)=log_{5}(1-x)+2 is x= 3/4
Solve for x: log_{5}(7-x)=log_{5}(1-x)+2
The solution is x= 3/4