What is the answer to 3log_{2}(x+4)-5=10 ?

The answer to 3log_{2}(x+4)-5=10 is x=28

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3log_{2}(x+4)-5=10

3 lo g_{2} (x + 4) - 5 = 10

x = 28

Solution steps

3 lo g_{2} (x + 4) - 5 = 10

Move

5

to the right side

3 lo g_{2} (x + 4) = 15

Divide both sides by

3

lo g_{2} (x + 4) = 5

Apply log rules

x + 4 = 32

Solve

x + 4 = 32 : x = 28

x = 28

Verify Solutions:

x = 28

True

The solution is

x = 28

a, x = lo g_{10} (a)

lo g_{5} (x + 3) - lo g_{5} (x - 1) = 1

lo g_{10} (\frac{1}{x}) = 8.89

ln (x) + x = 5

3 ln (x) - ln (x) - ln (9) = 0

What is the answer to 3log_{2}(x+4)-5=10 ?
The answer to 3log_{2}(x+4)-5=10 is x=28
Solve for x: 3log_{2}(x+4)-5=10
The solution is x=28