What is the answer to ln(x-4)+ln(4x+1)=9 ?

The answer to ln(x-4)+ln(4x+1)=9 is x=(15+sqrt(16e^9+289))/8

Solve for x: ln(x-4)+ln(4x+1)=9

The solution is x=(15+sqrt(16e^9+289))/8

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ln (x - 4) + ln (4 x + 1) = 9

x = \frac{15 + 16 e ^{9} + 289}{8}

Decimal Notation

x = 46.93370 \dots

Solution steps

ln (x - 4) + ln (4 x + 1) = 9

Apply log rules

(x - 4) (4 x + 1) = e^{9}

Solve

(x - 4) (4 x + 1) = e^{9} : x = \frac{15 + 16 e ^{9} + 289}{8}, x = \frac{15 - 16 e ^{9} + 289}{8}

x = \frac{15 + 16 e ^{9} + 289}{8}, x = \frac{15 - 16 e ^{9} + 289}{8}

Verify Solutions:

x = \frac{15 + 16 e ^{9} + 289}{8}

True

, x = \frac{15 - 16 e ^{9} + 289}{8}

False

The solution is

x = \frac{15 + 16 e ^{9} + 289}{8}

2 ln (x - 3) + ln (x + 8) = 3 ln (x)

lo g_{2} (x - 1) + lo g_{2} (x + 2) = 2

lo g_{2} (3 x + 1) = 2

lo g_{b} (3) = \frac{1}{4}

n lo g_{10} (n) = 3.6 \cdot 1 0^{13}

What is the answer to ln(x-4)+ln(4x+1)=9 ?
The answer to ln(x-4)+ln(4x+1)=9 is x=(15+sqrt(16e^9+289))/8
Solve for x: ln(x-4)+ln(4x+1)=9
The solution is x=(15+sqrt(16e^9+289))/8