What is the answer to log_{8}(x)+log_{9}(x)=1 ?

The answer to log_{8}(x)+log_{9}(x)=1 is x=9^{(3log_{9}(2))/(1+3log_{9)(2)}}

Solve for x: log_{8}(x)+log_{9}(x)=1

The solution is x=9^{(3log_{9}(2))/(1+3log_{9)(2)}}

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lo g_{8} (x) + lo g_{9} (x) = 1

x = 9^{\frac{3 l o g _{9} ( 2 )}{1 + 3 l o g _{9} ( 2 )}}

Decimal Notation

x = 2.91058 \dots

Solution steps

lo g_{8} (x) + lo g_{9} (x) = 1

Apply log rules

x = 9^{\frac{3 l o g _{9} ( 2 )}{1 + 3 l o g _{9} ( 2 )}}

Verify Solutions:

x = 9^{\frac{3 l o g _{9} ( 2 )}{1 + 3 l o g _{9} ( 2 )}}

True

The solution is

x = 9^{\frac{3 l o g _{9} ( 2 )}{1 + 3 l o g _{9} ( 2 )}}

lo g_{2} (x) - 8 lo g_{x^{2}} (2) = 3

lo g_{2} (x + 6) = 5

lo g_{9} (x - 2) = 2

lo g_{a} (\frac{16}{81}) = - 4

ln (x + 5) + ln (x - 3) = 2 ln (x)

What is the answer to log_{8}(x)+log_{9}(x)=1 ?
The answer to log_{8}(x)+log_{9}(x)=1 is x=9^{(3log_{9}(2))/(1+3log_{9)(2)}}
Solve for x: log_{8}(x)+log_{9}(x)=1
The solution is x=9^{(3log_{9}(2))/(1+3log_{9)(2)}}