What is the answer to 2z+4(z+1)=5-0z ?

The answer to 2z+4(z+1)=5-0z is z= 1/6

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2z+4(z+1)=5-0z

2 z + 4 (z + 1) = 5 - 0 z

z = \frac{1}{6}

Decimal Notation

z = 0.16666 \dots

Solution steps

2 z + 4 (z + 1) = 5 - 0 \cdot z

Apply rule

0 \cdot a = 0

2 z + 4 (z + 1) = 5 - 0

Subtract the numbers:

5 - 0 = 5

2 z + 4 (z + 1) = 5

Expand

4 (z + 1) : 4 z + 4

2 z + 4 z + 4 = 5

Add similar elements:

2 z + 4 z = 6 z

6 z + 4 = 5

Move

4

to the right side

6 z = 1

Divide both sides by

6

z = \frac{1}{6}

64 v^{4} - 225 w^{10}

36 x^{2} y - 9 y

12 5^{\frac{- 3}{4}} \cdot 5^{\frac{- 3}{4}}

- 5 (x + 6) - 10 = 10

7 y + 14