What is the answer to 0.25=(ln(4x))/(ln(2x)) ?

The answer to 0.25=(ln(4x))/(ln(2x)) is x= 1/(e^{\frac{7ln(2)){3}}}

Solve for x: 0.25=(ln(4x))/(ln(2x))

The solution is x= 1/(e^{\frac{7ln(2)){3}}}

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0.25 = \frac{ln ( 4 x )}{ln ( 2 x )}

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Decimal Notation

x = 0.19842 \dots

Solution steps

0.25 = \frac{ln ( 4 x )}{ln ( 2 x )}

Multiply both sides by

ln (2 x)

0.25 ln (2 x) = \frac{ln ( 4 x )}{ln ( 2 x )} ln (2 x)

Simplify

0.25 ln (2 x) = ln (4 x)

Apply log rules

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

x - ln (\frac{1}{x}) = 2

ln (ln (9 x)) = 0

ln (3 x + 4) - ln (2 x + 8) = 0

2 lo g_{x} (x + 2) = 3

lo g_{2} (x) + 1 = lo g_{4} (x)

What is the answer to 0.25=(ln(4x))/(ln(2x)) ?
The answer to 0.25=(ln(4x))/(ln(2x)) is x= 1/(e^{\frac{7ln(2)){3}}}
Solve for x: 0.25=(ln(4x))/(ln(2x))
The solution is x= 1/(e^{\frac{7ln(2)){3}}}