What is the answer to log_{4}(4x)+2log_{4}(4)=0 ?

The answer to log_{4}(4x)+2log_{4}(4)=0 is x= 1/64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(4x)+2log_{4}(4)=0

lo g_{4} (4 x) + 2 lo g_{4} (4) = 0

x = \frac{1}{64}

Decimal Notation

x = 0.015625

Solution steps

lo g_{4} (4 x) + 2 lo g_{4} (4) = 0

Move

2 lo g_{4} (4)

to the right side

lo g_{4} (4 x) = - 2 lo g_{4} (4)

Apply log rules

4 x = \frac{1}{16}

Solve

4 x = \frac{1}{16} : x = \frac{1}{64}

x = \frac{1}{64}

Verify Solutions:

x = \frac{1}{64}

True

The solution is

x = \frac{1}{64}

- lo g_{10} (x) = 11.45

ln (x) + ln (x - 8) = 3

lo g_{x + 1} (x + 3) = 2

lo g_{3} (4 x - 1) + lo g_{3} (x) = 1

lo g_{b} (7) - 2 lo g_{7} (b) + 1 = 0

What is the answer to log_{4}(4x)+2log_{4}(4)=0 ?
The answer to log_{4}(4x)+2log_{4}(4)=0 is x= 1/64
Solve for x: log_{4}(4x)+2log_{4}(4)=0
The solution is x= 1/64