What is the answer to x^{ln(4)}+4^{ln(x)}=32 ?

The answer to x^{ln(4)}+4^{ln(x)}=32 is x=16^{8201/11369}

Solve for x: x^{ln(4)}+4^{ln(x)}=32

The solution is x=16^{8201/11369}

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x^{l n (4)} + 4^{l n (x)} = 32

x = 1 6^{\frac{8201}{11369}}

Decimal Notation

x = 7.38905 \dots

Solution steps

x^{l n (4)} + 4^{l n (x)} = 32

Move

x^{l n (4)}

to the right side

4^{l n (x)} = 32 - x^{l n (4)}

Apply log rules

x^{2 l n (2)} = 32 - x^{2 l n (2)}

Solve

x^{2 l n (2)} = 32 - x^{2 l n (2)} : x = 1 6^{\frac{8201}{11369}}

x = 1 6^{\frac{8201}{11369}}

Verify Solutions:

x = 1 6^{\frac{8201}{11369}}

True

The solution is

x = 1 6^{\frac{8201}{11369}}

ln (x - 3) - ln (x + 5) = 4

0.72 = ln (y)

ln (x) + ln (2) = 1

2 lo g_{10} (x - 2) = 4 - x

0.25 = ln (y)

What is the answer to x^{ln(4)}+4^{ln(x)}=32 ?
The answer to x^{ln(4)}+4^{ln(x)}=32 is x=16^{8201/11369}
Solve for x: x^{ln(4)}+4^{ln(x)}=32
The solution is x=16^{8201/11369}