What is the answer to log_{8}(x+4)+log_{8}(x-3)=1 ?

The answer to log_{8}(x+4)+log_{8}(x-3)=1 is x=4

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log_{8}(x+4)+log_{8}(x-3)=1

lo g_{8} (x + 4) + lo g_{8} (x - 3) = 1

x = 4

Solution steps

lo g_{8} (x + 4) + lo g_{8} (x - 3) = 1

Apply log rules

(x + 4) (x - 3) = 8

Solve

(x + 4) (x - 3) = 8 : x = 4, x = - 5

x = 4, x = - 5

Verify Solutions:

x = 4

True

, x = - 5

False

The solution is

x = 4

lo g_{x} (x^{2}) = 6

lo g_{10} (x) = 2.1

lo g_{10} (x) = 2.3

lo g_{10} (x) = 2.4

lo g_{10} (x) = 2.9

What is the answer to log_{8}(x+4)+log_{8}(x-3)=1 ?
The answer to log_{8}(x+4)+log_{8}(x-3)=1 is x=4
Solve for x: log_{8}(x+4)+log_{8}(x-3)=1
The solution is x=4