What is the answer to log_{1/2}(2x+1)=-10 ?

The answer to log_{1/2}(2x+1)=-10 is x= 1023/2

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log_{1/2}(2x+1)=-10

lo g_{\frac{1}{2}} (2 x + 1) = - 10

x = \frac{1023}{2}

Decimal Notation

x = 511.5

Solution steps

lo g_{\frac{1}{2}} (2 x + 1) = - 10

Apply log rules

2 x + 1 = 1024

Solve

2 x + 1 = 1024 : x = \frac{1023}{2}

x = \frac{1023}{2}

lo g_{10} (a) = 2.655

lo g_{10} (x) = 1.6

lo g_{6} (x + 5) = 2

lo g_{a} (a) = 1

612733 = 48484 \cdot ln (x) + 67854

What is the answer to log_{1/2}(2x+1)=-10 ?
The answer to log_{1/2}(2x+1)=-10 is x= 1023/2
Solve for x: log_{1/2}(2x+1)=-10
The solution is x= 1023/2