What is the answer to 1+log_{2}(x)=log_{2}(x+5) ?

The answer to 1+log_{2}(x)=log_{2}(x+5) is x=5

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1+log_{2}(x)=log_{2}(x+5)

1 + lo g_{2} (x) = lo g_{2} (x + 5)

x = 5

Solution steps

1 + lo g_{2} (x) = lo g_{2} (x + 5)

Apply log rules

2 x = x + 5

Solve

2 x = x + 5 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{4} (3 x - 4) + lo g_{4} (x + 3) = 2

4.4 = - lo g_{10} (x)

lo g_{10} (x (20 - x)) = 2

\frac{ln ( p )}{ln ( 5 )} - 4 = 0

ln (\frac{x - 5}{x - 1}) = ln (6)

What is the answer to 1+log_{2}(x)=log_{2}(x+5) ?
The answer to 1+log_{2}(x)=log_{2}(x+5) is x=5
Solve for x: 1+log_{2}(x)=log_{2}(x+5)
The solution is x=5