What is the answer to log_{2}(x-3)+log_{2}(x)=2 ?

The answer to log_{2}(x-3)+log_{2}(x)=2 is x=4

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log_{2}(x-3)+log_{2}(x)=2

lo g_{2} (x - 3) + lo g_{2} (x) = 2

x = 4

Solution steps

lo g_{2} (x - 3) + lo g_{2} (x) = 2

Apply log rules

(x - 3) x = 4

Solve

(x - 3) x = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

False

The solution is

x = 4

lo g_{10} (x) = lo g_{10} (2)

ln (y) = 14

x = - 2 lo g_{2} (x)

x, y = - lo g_{10} (x)

lo g_{10} (x - \frac{2}{4}) = 2

What is the answer to log_{2}(x-3)+log_{2}(x)=2 ?
The answer to log_{2}(x-3)+log_{2}(x)=2 is x=4
Solve for x: log_{2}(x-3)+log_{2}(x)=2
The solution is x=4