What is the answer to log_{20}(x)=1+log_{20}(10) ?

The answer to log_{20}(x)=1+log_{20}(10) is x=200

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log_{20}(x)=1+log_{20}(10)

lo g_{20} (x) = 1 + lo g_{20} (10)

x = 200

Solution steps

lo g_{20} (x) = 1 + lo g_{20} (10)

Apply log rules

x = 200

2 lo g_{10} (x + 5) - lo g_{3} (9) = 2

ln (5 x + 4) = 3

ln (5 x + 4) = 0

lo g_{0.5} (x) = 2

ln (x + 10) + ln (x - 3) = 2 ln (x)

What is the answer to log_{20}(x)=1+log_{20}(10) ?
The answer to log_{20}(x)=1+log_{20}(10) is x=200
Solve for x: log_{20}(x)=1+log_{20}(10)
The solution is x=200