What is (m^{-1}+n^{-1})/((mn)^{-1)} ?

The solution to (m^{-1}+n^{-1})/((mn)^{-1)} is n+m

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simplify (m^{-1}+n^{-1})/((mn)^{-1)}

simplify

\frac{m ^{- 1} + n ^{- 1}}{( mn ) ^{- 1}}

n + m

Solution steps

\frac{m ^{- 1} + n ^{- 1}}{( mn ) ^{- 1}}

Simplify

m^{- 1} + n^{- 1} : \frac{n + m}{mn}

= \frac{\frac{n + m}{mn}}{( mn ) ^{- 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{n + m}{mn ( mn ) ^{- 1}}

Simplify

mn (mn)^{- 1} : 1

= \frac{n + m}{1}

Apply the fraction rule:

\frac{a}{1} = a

= n + m

9 x^{2} - 6 x - 8

- 3 \leq 1 - x < 2

6 - \frac{1}{2}

280 = 380 (1 - 1.9 x + 0.9 x^{2})

x + 65 = 125

What is (m^{-1}+n^{-1})/((mn)^{-1)} ?
The solution to (m^{-1}+n^{-1})/((mn)^{-1)} is n+m