What is the answer to log_{2}(x)=3-log_{2}(3x+10) ?

The answer to log_{2}(x)=3-log_{2}(3x+10) is x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x)=3-log_{2}(3x+10)

lo g_{2} (x) = 3 - lo g_{2} (3 x + 10)

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

lo g_{2} (x) = 3 - lo g_{2} (3 x + 10)

Add

lo g_{2} (3 x + 10)

to both sides

lo g_{2} (x) + lo g_{2} (3 x + 10) = 3 - lo g_{2} (3 x + 10) + lo g_{2} (3 x + 10)

Simplify

lo g_{2} (x) + lo g_{2} (3 x + 10) = 3

Apply log rules

x (3 x + 10) = 8

Solve

x (3 x + 10) = 8 : x = \frac{2}{3}, x = - 4

x = \frac{2}{3}, x = - 4

Verify Solutions:

x = \frac{2}{3}

True

, x = - 4

False

The solution is

x = \frac{2}{3}

lo g_{2} (x^{2} - 5 x + 14) = 3

lo g_{5} (x + 7) = - lo g_{5} (x + 3) + 1

lo g_{2} (x^{3}) = lo g_{8} (x)

lo g_{2} (x) + lo g_{4} (x) = 1

lo g_{2 a} (4) = 2

What is the answer to log_{2}(x)=3-log_{2}(3x+10) ?
The answer to log_{2}(x)=3-log_{2}(3x+10) is x= 2/3
Solve for x: log_{2}(x)=3-log_{2}(3x+10)
The solution is x= 2/3