What is the answer to log_{10}(x)+log_{10}(x+3)=2 ?

The answer to log_{10}(x)+log_{10}(x+3)=2 is x=(-3+sqrt(409))/2

Solve for x: log_{10}(x)+log_{10}(x+3)=2

The solution is x=(-3+sqrt(409))/2

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lo g_{10} (x) + lo g_{10} (x + 3) = 2

x = \frac{- 3 + 409}{2}

Decimal Notation

x = 8.61187 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 3) = 2

Apply log rules

x (x + 3) = 100

Solve

x (x + 3) = 100 : x = \frac{- 3 + 409}{2}, x = \frac{- 3 - 409}{2}

x = \frac{- 3 + 409}{2}, x = \frac{- 3 - 409}{2}

Verify Solutions:

x = \frac{- 3 + 409}{2}

True

, x = \frac{- 3 - 409}{2}

False

The solution is

x = \frac{- 3 + 409}{2}

lo g_{10} (x) \frac{1}{25} = - 2

0.367 = - lo g_{10} (x)

x, lo g_{x} (64) = - 2

3 lo g_{8} (x) - lo g_{x} (64) + 1 = 0

ln (3 x - 10) = 9

What is the answer to log_{10}(x)+log_{10}(x+3)=2 ?
The answer to log_{10}(x)+log_{10}(x+3)=2 is x=(-3+sqrt(409))/2
Solve for x: log_{10}(x)+log_{10}(x+3)=2
The solution is x=(-3+sqrt(409))/2