What is the answer to log_{2}(x)+log_{6}(x)=3 ?

The answer to log_{2}(x)+log_{6}(x)=3 is x=6^{(3log_{6}(2))/(1+log_{6)(2)}}

Solve for x: log_{2}(x)+log_{6}(x)=3

The solution is x=6^{(3log_{6}(2))/(1+log_{6)(2)}}

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lo g_{2} (x) + lo g_{6} (x) = 3

x = 6^{\frac{3 l o g _{6} ( 2 )}{1 + l o g _{6} ( 2 )}}

Decimal Notation

x = 4.47898 \dots

Solution steps

lo g_{2} (x) + lo g_{6} (x) = 3

Apply log rules

x = 6^{\frac{3 l o g _{6} ( 2 )}{1 + l o g _{6} ( 2 )}}

Verify Solutions:

x = 6^{\frac{3 l o g _{6} ( 2 )}{1 + l o g _{6} ( 2 )}}

True

The solution is

x = 6^{\frac{3 l o g _{6} ( 2 )}{1 + l o g _{6} ( 2 )}}

lo g_{0.02} (x) = - 1

13 ln (2 x + 3) = 15

lo g_{5} (x) = 2.6

lo g_{17} (x) = 6

lo g_{3} (2 x) = lo g_{3} (x + 5)

What is the answer to log_{2}(x)+log_{6}(x)=3 ?
The answer to log_{2}(x)+log_{6}(x)=3 is x=6^{(3log_{6}(2))/(1+log_{6)(2)}}
Solve for x: log_{2}(x)+log_{6}(x)=3
The solution is x=6^{(3log_{6}(2))/(1+log_{6)(2)}}