What is the answer to log_{2}(x^2-3x+2)=1 ?

The answer to log_{2}(x^2-3x+2)=1 is x=3,x=0

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log_{2}(x^2-3x+2)=1

lo g_{2} (x^{2} - 3 x + 2) = 1

x = 3, x = 0

Solution steps

lo g_{2} (x^{2} - 3 x + 2) = 1

Apply log rules

x^{2} - 3 x + 2 = 2

Solve

x^{2} - 3 x + 2 = 2 : x = 3, x = 0

x = 3, x = 0

lo g_{2 x - 1} (3.5 x^{2} - 2.5 x) = 2

2 lo g_{b} (5) = lo g_{b} (x)

lo g_{3} (x) = lo g_{x} (9)

lo g_{x} (16) = lo g_{2} (x)

ln (x) = \frac{6907756}{1000000}

What is the answer to log_{2}(x^2-3x+2)=1 ?
The answer to log_{2}(x^2-3x+2)=1 is x=3,x=0
Solve for x: log_{2}(x^2-3x+2)=1
The solution is x=3,x=0