What is the answer to log_{10}(x)-log_{10}(2)=2 ?

The answer to log_{10}(x)-log_{10}(2)=2 is x=200

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log_{10}(x)-log_{10}(2)=2

lo g_{10} (x) - lo g_{10} (2) = 2

x = 200

Solution steps

lo g_{10} (x) - lo g_{10} (2) = 2

Move

lo g_{10} (2)

to the right side

lo g_{10} (x) = 2 + lo g_{10} (2)

Apply log rules

x = 200

Verify Solutions:

x = 200

True

The solution is

x = 200

x, y^{2} = ln (x + y)

y, ln (y) = x - 2

lo g_{3} (2 x + 1) = 4

lo g_{10} (- m + 2) = 4

ln (3 x - 19) = 8

What is the answer to log_{10}(x)-log_{10}(2)=2 ?
The answer to log_{10}(x)-log_{10}(2)=2 is x=200
Solve for x: log_{10}(x)-log_{10}(2)=2
The solution is x=200