What is the answer to -ln(x)=ln(x^{-1}) ?

The answer to -ln(x)=ln(x^{-1}) is x>0

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-ln(x)=ln(x^{-1})

- ln (x) = ln (x^{- 1})

x > 0

Solution steps

- ln (x) = ln (x^{- 1})

Apply log rules

- ln (x) = (- 1) ln (x)

Rewrite the equation with

ln (x) = u

- u = (- 1) u

Solve

- u = (- 1) u :

True for all

u

True for all u

Verify Solutions:

x > 0

The solution is

x > 0

4 lo g_{10} (3 x) = 3

lo g_{3} (4 x - 19) = 4

2 ln (6 x - 3) + 5 = 15

lo g_{3} (d) = 2

lo g_{2} (8) + lo g_{2} (x) = 5

What is the answer to -ln(x)=ln(x^{-1}) ?
The answer to -ln(x)=ln(x^{-1}) is x>0
Solve for x: -ln(x)=ln(x^{-1})
The solution is x>0