What is the answer to ln(x)+2x-4=0 ?

The answer to ln(x)+2x-4=0 is x=(\W_{0}(2e^4))/2

Solve for x: ln(x)+2x-4=0

The solution is x=(\W_{0}(2e^4))/2

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ln (x) + 2 x - 4 = 0

x = \frac{W _{0} ( 2 e ^{4} )}{2}

Decimal Notation

x = 1.72685 \dots

Solution steps

ln (x) + 2 x - 4 = 0

Move

2 x

to the right side

ln (x) - 4 = - 2 x

Move

4

to the right side

ln (x) = - 2 x + 4

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{- 2 x + 4}

Simplify

e^{l n (x)} : x

x = e^{- 2 x + 4}

Solve

x = e^{- 2 x + 4} : x = \frac{W _{0} ( 2 e ^{4} )}{2}

x = \frac{W _{0} ( 2 e ^{4} )}{2}

Verify Solutions:

x = \frac{W _{0} ( 2 e ^{4} )}{2}

True

The solution is

x = \frac{W _{0} ( 2 e ^{4} )}{2}

lo g_{3} (x - 1) = 1

x, lo g_{x} (2 y) = 3

lo g_{2} (x) + lo g_{2} (x - 4) = 1

lo g_{10} (x) = 1 0^{6}

lo g_{x} (m) = n + 2

What is the answer to ln(x)+2x-4=0 ?
The answer to ln(x)+2x-4=0 is x=(\W_{0}(2e^4))/2
Solve for x: ln(x)+2x-4=0
The solution is x=(\W_{0}(2e^4))/2