What is the answer to log_{2}(x+6)+log_{2}(x+3)=2 ?

The answer to log_{2}(x+6)+log_{2}(x+3)=2 is x=-2

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log_{2}(x+6)+log_{2}(x+3)=2

lo g_{2} (x + 6) + lo g_{2} (x + 3) = 2

x = - 2

Solution steps

lo g_{2} (x + 6) + lo g_{2} (x + 3) = 2

Apply log rules

(x + 6) (x + 3) = 4

Solve

(x + 6) (x + 3) = 4 : x = - 2, x = - 7

x = - 2, x = - 7

Verify Solutions:

x = - 2

True

, x = - 7

False

The solution is

x = - 2

0.87 = lo g_{x} (x)

9 lo g_{5} (x) = 25 lo g_{x} (5)

y, ln (y - 2) = x^{2} + 2

4 ln (6 x - 2) + 5 = 13

lo g_{5} (x^{3}) - 6 = 0

What is the answer to log_{2}(x+6)+log_{2}(x+3)=2 ?
The answer to log_{2}(x+6)+log_{2}(x+3)=2 is x=-2
Solve for x: log_{2}(x+6)+log_{2}(x+3)=2
The solution is x=-2