What is the answer to 2ln(x)=-x+4 ?

The answer to 2ln(x)=-x+4 is x=2\W_{0}((e^2)/2)

Solve for x: 2ln(x)=-x+4

The solution is x=2\W_{0}((e^2)/2)

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2 ln (x) = - x + 4

x = 2 W_{0} (\frac{e ^{2}}{2})

Decimal Notation

x = 2.31831 \dots

Solution steps

2 ln (x) = - x + 4

Divide both sides by

2

ln (x) = \frac{- x + 4}{2}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{\frac{- x + 4}{2}}

Simplify

e^{l n (x)} : x

x = e^{\frac{- x + 4}{2}}

Solve

x = e^{\frac{- x + 4}{2}} : x = 2 W_{0} (\frac{e ^{2}}{2})

x = 2 W_{0} (\frac{e ^{2}}{2})

Verify Solutions:

x = 2 W_{0} (\frac{e ^{2}}{2})

True

The solution is

x = 2 W_{0} (\frac{e ^{2}}{2})

lo g_{m} (81) = 4

2 ln (x) + (ln (x))^{2} = 0

lo g_{x} (\frac{1}{125}) = - 3

lo g_{5} (x - 4) = 2

ln (\frac{25}{25 - y}) = ln (y)

What is the answer to 2ln(x)=-x+4 ?
The answer to 2ln(x)=-x+4 is x=2\W_{0}((e^2)/2)
Solve for x: 2ln(x)=-x+4
The solution is x=2\W_{0}((e^2)/2)