What is the answer to 6ln(3x-7)+12=-6 ?

The answer to 6ln(3x-7)+12=-6 is x=(1+7e^3)/(3e^3)

Solve for x: 6ln(3x-7)+12=-6

The solution is x=(1+7e^3)/(3e^3)

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6 ln (3 x - 7) + 12 = - 6

x = \frac{1 + 7 e ^{3}}{3 e ^{3}}

Decimal Notation

x = 2.34992 \dots

Solution steps

6 ln (3 x - 7) + 12 = - 6

Move

12

to the right side

6 ln (3 x - 7) = - 18

Divide both sides by

6

ln (3 x - 7) = - 3

Apply log rules

3 x - 7 = \frac{1}{e ^{3}}

Solve

3 x - 7 = \frac{1}{e ^{3}} : x = \frac{1 + 7 e ^{3}}{3 e ^{3}}

x = \frac{1 + 7 e ^{3}}{3 e ^{3}}

Verify Solutions:

x = \frac{1 + 7 e ^{3}}{3 e ^{3}}

True

The solution is

x = \frac{1 + 7 e ^{3}}{3 e ^{3}}

x, y^{2} = ln (x)

x, 0 = ln (x - y)

lo g_{25} (x^{2}) = 2

\frac{ln ( x )}{x} = 1

lo g_{10} (\frac{1}{x}) = 9.716

What is the answer to 6ln(3x-7)+12=-6 ?
The answer to 6ln(3x-7)+12=-6 is x=(1+7e^3)/(3e^3)
Solve for x: 6ln(3x-7)+12=-6
The solution is x=(1+7e^3)/(3e^3)