What is the answer to log_{2}((x+3)^2)=4 ?

The answer to log_{2}((x+3)^2)=4 is x=1,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}((x+3)^2)=4

lo g_{2} ((x + 3)^{2}) = 4

x = 1, x = - 7

Solution steps

lo g_{2} ((x + 3)^{2}) = 4

Apply log rules

(x + 3)^{2} = 16

Solve

(x + 3)^{2} = 16 : x = 1, x = - 7

x = 1, x = - 7

7.5 = - lo g_{10} (x)

ln (3) - ln (x + 5) - ln (x) = 0

lo g_{x} (\frac{1}{4}) = - 1

ln (- x) = 0

lo g_{2} (x - 1) = 3

What is the answer to log_{2}((x+3)^2)=4 ?
The answer to log_{2}((x+3)^2)=4 is x=1,x=-7
Solve for x: log_{2}((x+3)^2)=4
The solution is x=1,x=-7