What is the answer to log_{6}(7x)+2log_{6}(5)=0 ?

The answer to log_{6}(7x)+2log_{6}(5)=0 is x= 1/175

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log_{6}(7x)+2log_{6}(5)=0

lo g_{6} (7 x) + 2 lo g_{6} (5) = 0

x = \frac{1}{175}

Decimal Notation

x = 0.00571 \dots

Solution steps

lo g_{6} (7 x) + 2 lo g_{6} (5) = 0

Move

2 lo g_{6} (5)

to the right side

lo g_{6} (7 x) = - 2 lo g_{6} (5)

Apply log rules

7 x = \frac{1}{25}

Solve

7 x = \frac{1}{25} : x = \frac{1}{175}

x = \frac{1}{175}

Verify Solutions:

x = \frac{1}{175}

True

The solution is

x = \frac{1}{175}

x, lo g_{5} (x) = y + 9

lo g_{4} (x) = lo g_{10} (64)

x, z = ln (x + y^{2})

lo g_{12} (x) = lo g_{4} (9 x)

ln (ln (x)) = - 1.2

What is the answer to log_{6}(7x)+2log_{6}(5)=0 ?
The answer to log_{6}(7x)+2log_{6}(5)=0 is x= 1/175
Solve for x: log_{6}(7x)+2log_{6}(5)=0
The solution is x= 1/175