What is the answer to ln(x^2)+log_{10}(7x)=2 ?

The answer to ln(x^2)+log_{10}(7x)=2 is x=10^{(2log_{10}(e)-log_{10}(7)log_{10}(e))/(2+log_{10)(e)}}

Solve for x: ln(x^2)+log_{10}(7x)=2

The solution is x=10^{(2log_{10}(e)-log_{10}(7)log_{10}(e))/(2+log_{10)(e)}}

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ln (x^{2}) + lo g_{10} (7 x) = 2

x = 1 0^{\frac{2 l o g _{10} ( e ) - l o g _{10} ( 7 ) l o g _{10} ( e )}{2 + l o g _{10} ( e )}}

Decimal Notation

x = 1.60709 \dots

Solution steps

ln (x^{2}) + lo g_{10} (7 x) = 2

Apply log rules

x = 1 0^{\frac{2 l o g _{10} ( e ) - l o g _{10} ( 7 ) l o g _{10} ( e )}{2 + l o g _{10} ( e )}}

Verify Solutions:

x = 1 0^{\frac{2 l o g _{10} ( e ) - l o g _{10} ( 7 ) l o g _{10} ( e )}{2 + l o g _{10} ( e )}}

True

The solution is

x = 1 0^{\frac{2 l o g _{10} ( e ) - l o g _{10} ( 7 ) l o g _{10} ( e )}{2 + l o g _{10} ( e )}}

lo g_{2} (2 x + 4) - lo g_{2} (x - 4) = 3

lo g_{3} (m + 4) - 3 = - 4

lo g_{2} (x^{2}) = 0

lo g_{2} (x) - 5 lo g_{10} (x) = 84

lo g_{2} (a) = 5

What is the answer to ln(x^2)+log_{10}(7x)=2 ?
The answer to ln(x^2)+log_{10}(7x)=2 is x=10^{(2log_{10}(e)-log_{10}(7)log_{10}(e))/(2+log_{10)(e)}}
Solve for x: ln(x^2)+log_{10}(7x)=2
The solution is x=10^{(2log_{10}(e)-log_{10}(7)log_{10}(e))/(2+log_{10)(e)}}