What is the answer to log_{6}(x-10)+log_{6}(7)=2 ?

The answer to log_{6}(x-10)+log_{6}(7)=2 is x= 106/7

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log_{6}(x-10)+log_{6}(7)=2

lo g_{6} (x - 10) + lo g_{6} (7) = 2

x = \frac{106}{7}

Decimal

x = 15.14285 \dots

Solution steps

lo g_{6} (x - 10) + lo g_{6} (7) = 2

Move

lo g_{6} (7)

to the right side

lo g_{6} (x - 10) = 2 - lo g_{6} (7)

Apply log rules

x - 10 = \frac{36}{7}

Solve

x - 10 = \frac{36}{7} : x = \frac{106}{7}

x = \frac{106}{7}

Verify Solutions:

x = \frac{106}{7}

True

The solution is

x = \frac{106}{7}

lo g_{10} (x) (8) = 3

lo g_{2} (x + 4) + lo g_{2} (x - 3) = 3

lo g_{3} (x) = 2 - lo g_{3} (x - 8)

0.76 = ln (x)

- lo g_{10} (x) = 6

What is the answer to log_{6}(x-10)+log_{6}(7)=2 ?
The answer to log_{6}(x-10)+log_{6}(7)=2 is x= 106/7
Solve for x: log_{6}(x-10)+log_{6}(7)=2
The solution is x= 106/7