What is the answer to solvefor x,ln(xy^2)=xy ?

The answer to solvefor x,ln(xy^2)=xy is x=-(\W(-1/y))/y

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solvefor x,ln(xy^2)=xy

solve for

x, ln (x y^{2}) = x y

x = - \frac{W ( - \frac{1}{y} )}{y}

Solution steps

ln (x y^{2}) = x y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x y^{2})} = e^{x y}

Simplify

e^{l n (x y^{2})} : x y^{2}

x y^{2} = e^{x y}

Solve

x y^{2} = e^{x y} : x = - \frac{W ( - \frac{1}{y} )}{y}

x = - \frac{W ( - \frac{1}{y} )}{y}

Verify Solutions:

x = - \frac{W ( - \frac{1}{y} )}{y}

True

The solution is

x = - \frac{W ( - \frac{1}{y} )}{y}

0.87 = ln (y)

lo g_{10} ((2 x - 3)^{3}) = 6

lo g_{4} (2 x) = lo g_{4} (10)

lo g_{2} (- 5 x + 7) = 1

y, ln (y) = 3 t + 2

What is the answer to solvefor x,ln(xy^2)=xy ?
The answer to solvefor x,ln(xy^2)=xy is x=-(\W(-1/y))/y