What is the answer to 8^x=5^{2x-1} ?

The answer to 8^x=5^{2x-1} is x=(ln(5))/(2ln(5)-3ln(2))

Solve for x: 8^x=5^{2x-1}

The solution is x=(ln(5))/(2ln(5)-3ln(2))

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8^{x} = 5^{2 x - 1}

x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

Decimal Notation

x = 1.41248 \dots

Solution steps

8^{x} = 5^{2 x - 1}

Apply exponent rules

x ln (8) = (2 x - 1) ln (5)

Solve

x ln (8) = (2 x - 1) ln (5) : x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

\frac{7 x - 4}{3} - \frac{5 - 8 x}{- 3} \geq \frac{4 x - 7}{3}

x + 6 = 0

(- 2)^{2} - 2 (- 2)

\frac{6 x + 4}{3} = \frac{5 x - 5}{8}

7 (x - 1) = 3 (x + \frac{1}{3})

What is the answer to 8^x=5^{2x-1} ?
The answer to 8^x=5^{2x-1} is x=(ln(5))/(2ln(5)-3ln(2))
Solve for x: 8^x=5^{2x-1}
The solution is x=(ln(5))/(2ln(5)-3ln(2))