What is the answer to -0.73=20log_{10}(x/5) ?

The answer to -0.73=20log_{10}(x/5) is x=(5^{0.9635})/(2^{0.0365)}

Solve for x: -0.73=20log_{10}(x/5)

The solution is x=(5^{0.9635})/(2^{0.0365)}

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- 0.73 = 20 lo g_{10} (\frac{x}{5})

x = \frac{5 ^{0.9635}}{2 ^{0.0365}}

Decimal Notation

x = 4.59695 \dots

Solution steps

- 0.73 = 20 lo g_{10} (\frac{x}{5})

Switch sides

20 lo g_{10} (\frac{x}{5}) = - 0.73

Divide both sides by

20

lo g_{10} (\frac{x}{5}) = - 0.0365

Apply log rules

\frac{x}{5} = 1 0^{- 0.0365}

Multiply both sides by

5

\frac{x}{5} \cdot 5 = 1 0^{- 0.0365} \cdot 5

Simplify

1 0^{- 0.0365} \cdot 5 : \frac{5 ^{0.9635}}{2 ^{0.0365}}

x = \frac{5 ^{0.9635}}{2 ^{0.0365}}

Verify Solutions:

x = \frac{5 ^{0.9635}}{2 ^{0.0365}}

True

The solution is

x = \frac{5 ^{0.9635}}{2 ^{0.0365}}

lo g_{3} (x) + lo g_{3} (x - 24) = 4

lo g_{\frac{1}{2}} (4 x - 9) = 4

lo g_{10} (9 x) = 3

lo g_{8} (5 x + 4) = 3 x - 4

lo g_{2} ((r + 17)^{2}) = 4

What is the answer to -0.73=20log_{10}(x/5) ?
The answer to -0.73=20log_{10}(x/5) is x=(5^{0.9635})/(2^{0.0365)}
Solve for x: -0.73=20log_{10}(x/5)
The solution is x=(5^{0.9635})/(2^{0.0365)}