What is the answer to 4ln(7x+4)+1=13 ?

The answer to 4ln(7x+4)+1=13 is x=(e^3-4)/7

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4ln(7x+4)+1=13

4 ln (7 x + 4) + 1 = 13

x = \frac{e ^{3} - 4}{7}

Decimal Notation

x = 2.29793 \dots

Solution steps

4 ln (7 x + 4) + 1 = 13

Move

1

to the right side

4 ln (7 x + 4) = 12

Divide both sides by

4

ln (7 x + 4) = 3

Apply log rules

7 x + 4 = e^{3}

Solve

7 x + 4 = e^{3} : x = \frac{e ^{3} - 4}{7}

x = \frac{e ^{3} - 4}{7}

Verify Solutions:

x = \frac{e ^{3} - 4}{7}

True

The solution is

x = \frac{e ^{3} - 4}{7}

3 lo g_{10} (2 x + 6) = x + 2

13 = - lo g_{10} (x)

ln (e x^{3}) = 2

lo g_{3} (x - 2) = 0

x, 36 = 4 ln (x - 1)

What is the answer to 4ln(7x+4)+1=13 ?
The answer to 4ln(7x+4)+1=13 is x=(e^3-4)/7
Solve for x: 4ln(7x+4)+1=13
The solution is x=(e^3-4)/7