What is the answer to log_{10}(x+1)=log_{10}(x)+1 ?

The answer to log_{10}(x+1)=log_{10}(x)+1 is x= 1/9

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log_{10}(x+1)=log_{10}(x)+1

lo g_{10} (x + 1) = lo g_{10} (x) + 1

x = \frac{1}{9}

Decimal Notation

x = 0.11111 \dots

Solution steps

lo g_{10} (x + 1) = lo g_{10} (x) + 1

Apply log rules

x + 1 = x \cdot 10

Solve

x + 1 = x \cdot 10 : x = \frac{1}{9}

x = \frac{1}{9}

Verify Solutions:

x = \frac{1}{9}

True

The solution is

x = \frac{1}{9}

lo g_{3} (\frac{1}{x}) = - 2

lo g_{2} (x - 2) - 7 = - lo g_{2} (x + 6)

lo g_{10} (x - 21) = 2 - lo g_{10} (x)

lo g_{5} (x + 2) = 1 - lo g_{5} (x + 6)

0.32 = ln (x)

What is the answer to log_{10}(x+1)=log_{10}(x)+1 ?
The answer to log_{10}(x+1)=log_{10}(x)+1 is x= 1/9
Solve for x: log_{10}(x+1)=log_{10}(x)+1
The solution is x= 1/9