What is the answer to log_{2}(x)log_{8}(x)=12 ?

The answer to log_{2}(x)log_{8}(x)=12 is x=64,x= 1/64

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log_{2}(x)log_{8}(x)=12

lo g_{2} (x) lo g_{8} (x) = 12

x = 64, x = \frac{1}{64}

Decimal Notation

x = 64, x = 0.015625

Solution steps

lo g_{2} (x) lo g_{8} (x) = 12

Apply log rules

3 lo g_{8} (x)^{2} = 12

Rewrite the equation with

lo g_{8} (x) = u

3 u^{2} = 12

Solve

3 u^{2} = 12 : u = 4, u = - 4

u = 4, u = - 4

Substitute back

u = lo g_{8} (x),

solve for

x

Solve

lo g_{8} (x) = 4 : x = 64

Solve

lo g_{8} (x) = - 4 : x = \frac{1}{64}

x = 64, x = \frac{1}{64}

Verify Solutions:

x = 64

True

, x = \frac{1}{64}

True

The solutions are

x = 64, x = \frac{1}{64}

x, 2 ln (3 x^{2} + 1) - 13 = 0

lo g_{7} (9 x) - 2 lo g_{7} (6) = 1

(ln (x))^{2} - 14 = 5 ln (x)

3.82 = - lo g_{10} (x)

x^{2} ln (x) = 0

What is the answer to log_{2}(x)log_{8}(x)=12 ?
The answer to log_{2}(x)log_{8}(x)=12 is x=64,x= 1/64
Solve for x: log_{2}(x)log_{8}(x)=12
The solution is x=64,x= 1/64