What is the answer to 4log_{10}(2x-2)=2 ?

The answer to 4log_{10}(2x-2)=2 is x=(sqrt(10)+2)/2

Solve for x: 4log_{10}(2x-2)=2

The solution is x=(sqrt(10)+2)/2

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4 lo g_{10} (2 x - 2) = 2

x = \frac{10 + 2}{2}

Decimal Notation

x = 2.58113 \dots

Solution steps

4 lo g_{10} (2 x - 2) = 2

Divide both sides by

4

lo g_{10} (2 x - 2) = \frac{1}{2}

Apply log rules

2 x - 2 = 10

Solve

2 x - 2 = 10 : x = \frac{10 + 2}{2}

x = \frac{10 + 2}{2}

Verify Solutions:

x = \frac{10 + 2}{2}

True

The solution is

x = \frac{10 + 2}{2}

lo g_{3} (2 x - 4) = 2

5 ln (2 x + 3) + 6 = 16

5 lo g_{2} (x) = - 2

lo g_{10} (1 + x) = 0.599

4 ln (4 - 3 x) = 12

What is the answer to 4log_{10}(2x-2)=2 ?
The answer to 4log_{10}(2x-2)=2 is x=(sqrt(10)+2)/2
Solve for x: 4log_{10}(2x-2)=2
The solution is x=(sqrt(10)+2)/2