What is the answer to log_{7}(9x+4)+log_{7}(x+2)=3 ?

The answer to log_{7}(9x+4)+log_{7}(x+2)=3 is x=5

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log_{7}(9x+4)+log_{7}(x+2)=3

lo g_{7} (9 x + 4) + lo g_{7} (x + 2) = 3

x = 5

Solution steps

lo g_{7} (9 x + 4) + lo g_{7} (x + 2) = 3

Apply log rules

(9 x + 4) (x + 2) = 343

Solve

(9 x + 4) (x + 2) = 343 : x = 5, x = - \frac{67}{9}

x = 5, x = - \frac{67}{9}

Verify Solutions:

x = 5

True

, x = - \frac{67}{9}

False

The solution is

x = 5

4 ln (8 x - 1) + 4 = - 4

ln (x) = 100

ln (x) = 2.1

lo g_{5} (x + 3) = 1 - lo g_{5} (x + 7)

x, 4.83 = - lo g_{10} (x)

What is the answer to log_{7}(9x+4)+log_{7}(x+2)=3 ?
The answer to log_{7}(9x+4)+log_{7}(x+2)=3 is x=5
Solve for x: log_{7}(9x+4)+log_{7}(x+2)=3
The solution is x=5