What is the answer to ln(-x+1)-ln(3x+5)=ln(-6x+1) ?

The answer to ln(-x+1)-ln(3x+5)=ln(-6x+1) is x=-(13+sqrt(241))/(18),x=(sqrt(241)-13)/(18)

Solve for x: ln(-x+1)-ln(3x+5)=ln(-6x+1)

The solution is x=-(13+sqrt(241))/(18),x=(sqrt(241)-13)/(18)

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ln (- x + 1) - ln (3 x + 5) = ln (- 6 x + 1)

x = - \frac{13 + 241}{18}, x = \frac{241 - 13}{18}

Decimal Notation

x = - 1.58467 \dots, x = 0.14023 \dots

Solution steps

ln (- x + 1) - ln (3 x + 5) = ln (- 6 x + 1)

Add

ln (3 x + 5)

to both sides

ln (- x + 1) - ln (3 x + 5) + ln (3 x + 5) = ln (- 6 x + 1) + ln (3 x + 5)

Simplify

ln (- x + 1) = ln (- 6 x + 1) + ln (3 x + 5)

Apply log rules

- x + 1 = (- 6 x + 1) (3 x + 5)

Solve

- x + 1 = (- 6 x + 1) (3 x + 5) : x = - \frac{13 + 241}{18}, x = \frac{241 - 13}{18}

x = - \frac{13 + 241}{18}, x = \frac{241 - 13}{18}

Verify Solutions:

x = - \frac{13 + 241}{18}

True

, x = \frac{241 - 13}{18}

True

The solutions are

x = - \frac{13 + 241}{18}, x = \frac{241 - 13}{18}

a = \frac{1}{2} a ln (x)

ln (x) = 0.9

lo g_{3} (4 x + 5) = 1

lo g_{\frac{1}{5}} (x) = - 2

lo g_{10} (4) + lo g_{10} (x) = 2

What is the answer to ln(-x+1)-ln(3x+5)=ln(-6x+1) ?
The answer to ln(-x+1)-ln(3x+5)=ln(-6x+1) is x=-(13+sqrt(241))/(18),x=(sqrt(241)-13)/(18)
Solve for x: ln(-x+1)-ln(3x+5)=ln(-6x+1)
The solution is x=-(13+sqrt(241))/(18),x=(sqrt(241)-13)/(18)