What is the answer to log_{2}(x+1)+log_{2}(x+2)=1 ?

The answer to log_{2}(x+1)+log_{2}(x+2)=1 is x=0

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log_{2}(x+1)+log_{2}(x+2)=1

lo g_{2} (x + 1) + lo g_{2} (x + 2) = 1

x = 0

Solution steps

lo g_{2} (x + 1) + lo g_{2} (x + 2) = 1

Apply log rules

(x + 1) (x + 2) = 2

Solve

(x + 1) (x + 2) = 2 : x = 0, x = - 3

x = 0, x = - 3

Verify Solutions:

x = 0

True

, x = - 3

False

The solution is

x = 0

ln (1 - x) + ln (1 + x) = - 2

y, z = ln (y + 2) - ln (y + 1)

5000 lo g_{2} (n) = n

ln (x + 4) = 0

lo g_{x} (49) = \frac{2}{3}

What is the answer to log_{2}(x+1)+log_{2}(x+2)=1 ?
The answer to log_{2}(x+1)+log_{2}(x+2)=1 is x=0
Solve for x: log_{2}(x+1)+log_{2}(x+2)=1
The solution is x=0