What is the answer to log_{27}(a^2)=18 ?

The answer to log_{27}(a^2)=18 is a=27^9,a=-27^9

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log_{27}(a^2)=18

lo g_{27} (a^{2}) = 18

a = 2 7^{9}, a = - 2 7^{9}

Decimal Notation

a = 7625597484987, a = - 7625597484987

Solution steps

lo g_{27} (a^{2}) = 18

Apply log rules

a^{2} = 2 7^{18}

Solve

a^{2} = 2 7^{18} : a = 2 7^{9}, a = - 2 7^{9}

a = 2 7^{9}, a = - 2 7^{9}

lo g_{3} (4 - 3^{x - 1} - 1) = 2 x - 1

lo g_{3} (x) = 10

6 lo g_{5} (x) + 7 lo g_{2} (x) = 6

ln (x - 2) + ln (x) = 0

0.3 = lo g_{10} (x)

What is the answer to log_{27}(a^2)=18 ?
The answer to log_{27}(a^2)=18 is a=27^9,a=-27^9
Solve for a: log_{27}(a^2)=18
The solution is a=27^9,a=-27^9