What is the answer to log_{x}(81)+2log_{x}(729)=16 ?

The answer to log_{x}(81)+2log_{x}(729)=16 is x=3

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log_{x}(81)+2log_{x}(729)=16

lo g_{x} (81) + 2 lo g_{x} (729) = 16

x = 3

Solution steps

lo g_{x} (81) + 2 lo g_{x} (729) = 16

Apply log rules

\frac{ln ( 81 \cdot 72 9 ^{2} )}{ln ( x )} = 16

Multiply both sides by

ln (x)

\frac{ln ( 81 \cdot 72 9 ^{2} )}{ln ( x )} ln (x) = 16 ln (x)

Apply log rules

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

ln (x) = 4.1

ln (x) + ln (x + 1) = ln (30)

lo g_{7} (3 x + 2) - lo g_{7} (x - 2) = 1

lo g_{b} (128) = 7

2 - ln (7 - x) = 0

What is the answer to log_{x}(81)+2log_{x}(729)=16 ?
The answer to log_{x}(81)+2log_{x}(729)=16 is x=3
Solve for x: log_{x}(81)+2log_{x}(729)=16
The solution is x=3