What is the answer to log_{x-1}(145)=7 ?

The answer to log_{x-1}(145)=7 is x=\sqrt[7]{145}+1

Solve for x: log_{x-1}(145)=7

The solution is x=\sqrt[7]{145}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{x - 1} (145) = 7

Decimal Notation

x = 3.03594 \dots

Solution steps

lo g_{x - 1} (145) = 7

Apply log rules

\frac{1}{lo g _{145} ( x - 1 )} = 7

Multiply both sides by

lo g_{145} (x - 1)

\frac{1}{lo g _{145} ( x - 1 )} lo g_{145} (x - 1) = 7 lo g_{145} (x - 1)

Simplify

1 = 7 lo g_{145} (x - 1)

Switch sides

7 lo g_{145} (x - 1) = 1

Divide both sides by

7

lo g_{145} (x - 1) = \frac{1}{7}

Apply log rules

Solve

Verify Solutions:

True

The solution is

ln (2 x + 1) = - 4

ln (x) = 3.9

lo g_{x} (100) = \frac{2}{3}

ln (3 x) = 5

ln (3 x) = 7

What is the answer to log_{x-1}(145)=7 ?
The answer to log_{x-1}(145)=7 is x=\sqrt[7]{145}+1
Solve for x: log_{x-1}(145)=7
The solution is x=\sqrt[7]{145}+1