What is the answer to ln(x)+ln(x-1)=ln(4-x) ?

The answer to ln(x)+ln(x-1)=ln(4-x) is x=2

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ln(x)+ln(x-1)=ln(4-x)

ln (x) + ln (x - 1) = ln (4 - x)

x = 2

Solution steps

ln (x) + ln (x - 1) = ln (4 - x)

Apply log rules

x (x - 1) = 4 - x

Solve

x (x - 1) = 4 - x : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

False

The solution is

x = 2

ln (- 3 x + 5) = 6

lo g_{x} (\frac{1}{10}) = - 1

lo g_{4} (3 x - 5) = 3

lo g_{4} (3 x - 5) = 2

ln (3.4 x + 2.8) - 1.9 = - 5.9

What is the answer to ln(x)+ln(x-1)=ln(4-x) ?
The answer to ln(x)+ln(x-1)=ln(4-x) is x=2
Solve for x: ln(x)+ln(x-1)=ln(4-x)
The solution is x=2